Which statement is true about IPv4 and IPv6 addresses?

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Multiple Choice

Which statement is true about IPv4 and IPv6 addresses?

IPv4 and IPv6 addresses differ in length, notation, and built-in capabilities. IPv4 uses 32-bit addresses, typically written in dotted decimal like 192.168.0.1. IPv6 uses 128-bit addresses, written in hexadecimal and separated by colons (for example, 2001:0db8:85a3:0000:0000:8a2e:0370:7334), with many addresses able to be shortened using abbreviations. IPv6 also introduces easier autoconfiguration, such as stateless address autoconfiguration, allowing devices to configure themselves on a network, and it includes built-in security options (IPsec) for securing IP communications. In contrast, IPv4 does not have these features built into the core protocol and IPsec is optional rather than a fundamental part of IPv4. So the statement that IPv4 uses 32-bit addresses and IPv6 uses 128-bit addresses, with IPv6 offering longer notation plus simplified autoconfiguration and built-in security options, is correct.

IPv4 and IPv6 addresses differ in length, notation, and built-in capabilities. IPv4 uses 32-bit addresses, typically written in dotted decimal like 192.168.0.1. IPv6 uses 128-bit addresses, written in hexadecimal and separated by colons (for example, 2001:0db8:85a3:0000:0000:8a2e:0370:7334), with many addresses able to be shortened using abbreviations.

IPv6 also introduces easier autoconfiguration, such as stateless address autoconfiguration, allowing devices to configure themselves on a network, and it includes built-in security options (IPsec) for securing IP communications. In contrast, IPv4 does not have these features built into the core protocol and IPsec is optional rather than a fundamental part of IPv4.

So the statement that IPv4 uses 32-bit addresses and IPv6 uses 128-bit addresses, with IPv6 offering longer notation plus simplified autoconfiguration and built-in security options, is correct.

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